#-------------------------------------------------------------------------------

# Name: Project Euler: Problem 1

# Purpose: Find the sum of all the multiples of 3 or 5 below 1000.

#

# Author: Sebastián Torrente

#

# Comment: Easy problem. Nothing out of the ordinary.

# Comment 2: List comprenhesion is a thing of beauty.

#-------------------------------------------------------------------------------

def sumDiv(div1,div2,upto):

"""Calculate the sum of all the numbers below upto that can be divided by

div1 or div2"""

sum = 0

divlist = [x for x in range(upto) if (x % div1 == 0 or x % div2 == 0)]

for num in divlist: sum += num

return sum

if __name__ == '__main__':

print (sumDiv(3, 5, 1000))