Expected Behavior

Variable assignment without declaration when using object destructuring should work.

According to destructuring assignment in MDN

{a, b} = {a: 1, b: 2} is not valid stand-alone syntax, as the {a, b} on the left-hand side is considered a block and not an object literal.

However, ({a, b} = {a: 1, b: 2}) is valid, as is var {a, b} = {a: 1, b: 2}

Current Behavior

Currently the variable name on left-hand side part of the statement is not being changed by the obfuscator while the initial variable declaration is.

This is the obfuscator output for the function below:

functiontest(_0x4bb6ab){
	let_0x44c2ed=undefined;if(!![]){
		({
			a // <- notice how a is not obfuscated
		}=_0x4bb6ab);
	}console[_0x1b95('0x0')](_0x44c2ed);
}

Steps to Reproduce (for bugs)

1. Simply run the obfuscator for the code example given below

Your Environment

• Obfuscator version used: 0.18.1
• Node version used: 8.2.1 (although it does matter)

Stack trace

Minimal working example that will help to reproduce issue

function test(obj) {
    let a = undefined;
    if(true){
        ({a} = obj);
    }
    console.log(a);
    // this should print 1, running the same example after the obfuscation prints undefined
}

test({a: 1});